error with linear manipulation of table elements

Holonist · October 2014

Hi guys, I have the following problem:

I have an object with a progress bar. Whenever the progress advances far enough, an additional square gets lit up.

--Initialization of 24 squares
--
self.bars = {}
local k = 0
for i=1,24 do
	self.bars[i] = Geom.createRectAngle(0,0,10,10,0x115578)
	self.bars[i]:setPosition(self.x+5+(i%6)*15, self.y+8+(k*15))
	self:addChild(self.bars[i])
	if i%6 == 0 then
		k = k+1
	end
end

--Colortransforming of all available squares in the ENTER_FRAME event.
--self.framesElapsed is reset to zero once the progress reaches 100%
--
local prog = round((self.framesElapsed/self.framesNeeded)*#self.bars, 0)
 
if prog > 0 then
	for i=1, prog do
		self.bars[i]:setColorTransform(2,2,2,1)
	end
else
	for i=1, #self.bars do
		self.bars[i]:setColorTransform(1,1,1,1)
	end
end

So far the mechanism works, but there is one bug.
Please have a look at my video I uploaded, you will get what I want to do and what's the problem:

The first square to be color transformed is always the SECOND one in a row.
To my understanding, it should be the first one, according to my code.

Instead, the first square in a row will be the last one which gets color transformed.
Is this some kind of special behaviour of lua I missed out on?

Thanks in advance

keszegh · October 2014

well, i%6 takes these values:
1->1
2->2
3->3
4->4
5->5
6->0
and then you increase k
so no wonder it goes in this order.

try this:

self.bars = {}
local k = -1
for i=0,23 do
if i%6 == 0 then
k = k+1
end
self.bars[i] = Geom.createRectAngle(0,0,10,10,0x115578)
self.bars[i]:setPosition(self.x+5+(i%6)*15, self.y+8+(k*15))
self:addChild(self.bars[i])
end

Holonist · October 2014

i%6 is just responsible for the x-position of each square, the indexing (i itself) should remain 1-24

edit: ah now i get it, sorry. the squares are actually misaligned in the first place.
gonna try what you say

Holonist · October 2014

Works, you're the MVP.
I also had to write "self.bars[i+1]" instead of self.bars[i] so the second loop would be able to finish, too.

keszegh · October 2014

glad to hear it worked

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