Questions about lua

oleg · August 2019

Sorry for the baby question:
How to check that the table has a function? So far I have found a way out:if #a[1]==0 , Is it possible to do it differently?

	function test()
		print ("test1")
	end
 
    a={{p=test},234523}
 
	for i=1,2 do
		if #a[i]==0 then
			a[i].p()
		else 
			print(a[i])
		end
 
	end

oleg · August 2019

solved the problem:

	function test()
		print ("test1")
	end
 
    a={{test},0}
 
		if type(a[1])=="table" then
			a[1][1]()
 
		end

hgy29 · August 2019

why not just test for a function ?

function test()
		print ("test1")
	end
 
    a={test,0}
 
		if type(a[1])=="function" then
			a[1]()
		end

oleg · August 2019

hgy29 said:
why not just test for a function ?

Because I need to pass parameters to the function

	function test(param)
		print ("test1",param)
	end
 
    a={{test,23},0}
 
		if type(a[1])=="table" then
			a[1][1](a[1][2])
 
		end

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