Compare two values problem!?

GiderosFan

I tried to compare two values.
The first value i have saved in my settings the other is just an number.

my code looks like this:

counted_tested = sets:get("counted") counted_tested = counted_tested + 1 sets:set("counted", counted_tested, true) print(sets:get("counted")) --> gives me the correct number back     if sets:get("counted") <= 30 then --> gives me the error like this (attempt to compare number with nil)

so the error message is: attempt to compare number with nil

why this is nil i have set an number or?

tkhnoman

What is sets?
How get and set function written like?
It depends on the returned value.

pie

Do you have a default/starting num value on "counted" for the first iteration?

I think that you can also use or

counted_tested = sets:get("counted") or 1

GiderosFan

@tkhnoman sets is my settings.lua file that contains the counted value sorry i forgotten to explain this.

my settings file look like this:

local settings = { counted = 0, }

GiderosFan

@ pie

sets:get("counted") or 1

gives me the same error.

pie

@GiderosFan try

local settings = { "counted" = 0, }

pie

Two more things you can try:

1) check the type of your value

print("value type", type(counted_tested) )

If the value is saved as a number, but returned as string maybe it's not recognized as a "number in a string" which lua is supposed to do.
What is strange is that you have nil in the error and not "trying to compare number with string".

If that's the case, you can use tonumber(counted_tested) to "convert" it back.

2) instead of using the function as the parameter to your condition, try writing it "exploded"

local countTested = sets:get("counted") print("countTested: ", countTested ) --just to be sure if countTested <= 30 then..

GiderosFan

ahhh yes that was what i have searched to convert it with tonumber(....) thank you pie for the fast solution .

the code works yet thank you