how to print line number & module's name in the Output window

Comments

• asakharov Member

  June 2013 Accepted Answer

  function trace()
  local info = debug.getinfo(2)
  print("module=" ..info.short_src .. ", line=" .. info.currentline)
  end

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• AhBadiane Member

  June 2013

  thanks @asakharov , I really have to immerse myself in the doc LUA

  AhBadiane

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• OZApps Guru

  June 2013 edited June 2013

  @AhBadiane, you can also try the following code
  < removed code >

  twitter: @ozapps | http://www.oz-apps.com | http://howto.oz-apps.com | http://reviewme.oz-apps.com
  Author of Learn Lua for iOS Game Development from Apress ( http://www.apress.com/9781430246626 )
  Cool Vizify Profile at https://www.vizify.com/oz-apps

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• asakharov Member

  June 2013

  @OZApps, I tested my version and yours for 10 millions of traces.
  And my code about 10% faster.

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• OZApps Guru

  June 2013

  @asakharov, the code snip was more for usability, any number of print statements will slow down or reduce performance.

  twitter: @ozapps | http://www.oz-apps.com | http://howto.oz-apps.com | http://reviewme.oz-apps.com
  Author of Learn Lua for iOS Game Development from Apress ( http://www.apress.com/9781430246626 )
  Cool Vizify Profile at https://www.vizify.com/oz-apps

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