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Flip Sprite — Gideros Forum
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    Flip Sprite

    Tstar_oneTstar_one Member
    edited August 2013 in General questions
    Hello Guys i need help :D

    I want to flip an Sprite . if i do this with setSccaleX(-1) and setScaleY(-1) the Sprite is left from where the object shoud be
    so what i have to do ? i use Texture with Region for the Anmimation
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    Comments

    • ar2rsawseenar2rsawseen Maintainer
      edited August 2013
      I think setting anchor point to 0.5, 0.5 should solve that problem, have you tried? :)
      http://appcodingeasy.com/Gideros-Mobile
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    • Tstar_oneTstar_one Member
      hm yeah works :D but i need the AnchorPoint at 0 , 0 for Collision an other Functions :S is there any thing i can do ?
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    • ar2rsawseenar2rsawseen Maintainer
      hmm, what exactly your collision function does? Can't it use Sprite:getBounds() for collision determination?
      http://appcodingeasy.com/Gideros-Mobile
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    • Tstar_oneTstar_one Member
      edited August 2013
      Standard Code from the Forum :)

      function sprite:collision(sprite2)

      --Input (sprite2): another sprite to check for collision detection
      --Return: return true if the rectangles overlap otherwise return false

      -- self bottom < other sprite top
      if self:getY() + self:getHeight() < sprite2:getY() then
      return false
      end
      -- self top > other sprite bottom
      if self:getY() > sprite2:getY() + sprite2:getHeight() then
      return false
      end
      -- self left > other sprite right
      if self:getX() > sprite2:getX() + sprite2:getWidth() then
      return false
      end
      -- self right < other sprite left
      if self:getX() + self:getWidth() < sprite2:getX() then
      return false
      end

      return true
      end


      how can i include code here ? : )
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    • ar2rsawseenar2rsawseen Maintainer
      you most probably can replace it with this:
      function Sprite:collidesWith(sprite2)
	local x,y,w,h = self:getBounds(stage)
	local x2,y2,w2,h2 = sprite2:getBounds(stage)
 
	return not ((y+h < y2) or (y > y2+h2) or (x > x2+w2) or (x+w < x2))
end
      And about code inclusion:
      http://members.giderosmobile.com/knowledgebase.php?action=displayarticle&id=41

      ;)

      Likes: Tstar_one

      http://appcodingeasy.com/Gideros-Mobile
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    • Tstar_oneTstar_one Member
      Fantastic thank you very much again :D
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